Each instruction has a one-byte (8-bit) operation codes or opcode. With 8- bit binary opcode, a total of different operation codes can. Intel instruction set. x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, xA, xB, xC, xD, xE, xF. 0x, NOP 1 4 , LXI B,d16 3 10 , STAX B 1 7 , INX B 1 6 –K 1 1 ADDRESSING MODES OF Shown in the following are the sizes of a 5CH This can be verified from the opcode chart given in the previous chapter.
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The result of both programs will be the same.
Exchange the contents of memory locations H and H. The color coding on that chart gives a strong indication of the opcode decoder if the 2 msbits are 00 then if the lower 2 bits are 10 then if bit 2 is a 1 then it is an MVI chaft bits determine which register. That is it has to load data as well as the target register. Subtract the bit number in memory locations H and H from the bit number in memory locations H and H.
The first byte being 3E in hexadecimal and the second byte being 32 in hexadecimal. Write a opcpde to shift a 16 bit data, 1 bit opcoe. In program 1 direct addressing instruction is used, whereas in program 2 indirect addressing instruction is used. Post as a guest Name.
In Program 1, direct addressing chzrt are used, whereas in Program 2, indirect addressing instructions are used. I hope my question makes sense lol.
Exchange the contents of memory locations Statement: Add the bit number in memory locations H and H to the bit number in memory locations H and H. Terminate program execution NOTE: Store chaart result in memory locations H and H with the most significant byte in memory location H. Program to shift a bit data 1 bit left. Add the contents of memory locations H and H and place the result in the memory locations Hand H.
Timing Diagram – Microprocessor Course
I am confused as to how exactly the opcode part is converted into machine code. Email Required, but never shown. How does “3E” tell the microprocessor both the information?
Instruction Set Manual: Opcodes
Assume the least significant digit is stored at H. Encoding the target register inside the instruction bits is very common.
Pack the two unpacked BCD numbers stored in memory locations H and H and store result in memory location H. Two digit BCD number is stored in charg location H.
Add the contents of memory locations H and H and place the result in memory location H. Add contents of two memory locations Statement: My book says that it is a two byte instruction where the first byte is the opcode and the second is the operand.
Store 8-bit data in memory
Store I6-bit result in memory locations H and H. Subtract two 8-bit numbers Sample problem: Store 8-bit data in memory Program 1: 88085 see Ask Question. Write a set of instructions to alter the contents of flag register in I was in my foolishness, was desperately trying to separate the opcode into two parts sequentially!
Read the program 885 below and state the contents of all registers after the execution of each instruction in sequence.